(0.06+x)(x)=1.84*10^-3

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Solution for (0.06+x)(x)=1.84*10^-3 equation:



(0.06+x)(x)=1.84*10^-3
We move all terms to the left:
(0.06+x)(x)-(1.84*10^-3)=0
We add all the numbers together, and all the variables
(x+0.06)x-(1.84*10^-3)=0
We add all the numbers together, and all the variables
(x+0.06)x-0.00184=0
We multiply parentheses
x^2+0.06x-0.00184=0
a = 1; b = 0.06; c = -0.00184;
Δ = b2-4ac
Δ = 0.062-4·1·(-0.00184)
Δ = 0.01096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{0.01096}}{2*1}=\frac{-0.06-\sqrt{0.01096}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{0.01096}}{2*1}=\frac{-0.06+\sqrt{0.01096}}{2} $

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